Charge Crossing Technique When
Given Name, Write the Formula
The rules to follow are:
Suppose you must write the formula for sodium chloride. I'm sure you know the answer (NaCl), but let's pretend you don't.
Write down the Na+ and Cl¯ right next to each other, as in this image:
Move the positive charge (dropping the sign) to the subscript position of the anion:
Move the negative charge (dropping the sign) to the subscript position of the cation:
The result of all this moving is:
Since subscripts of one are not written, but understood to be present, the final answer is:
Write the formula for magnesium chloride.
Write down the Mg2+ and Cl¯ right next to each other, as in this image:
Move the positive charge (dropping the sign) to the subscript position of the anion:
Move the negative charge (dropping the sign) to the subscript position of the cation:
The result of all this moving is:
Since subscripts of one are not written, but understood to be present, the final answer is:
Write the formula for aluminum oxide.
Write down the Al3+ and O2¯ right next to each other, as in this image:
Move the positive charge (dropping the sign) to the subscript position of the anion:
Move the negative charge (dropping the sign) to the subscript position of the cation:
The result of all this moving is:
Notice that there is no fifth image in this problem. The Al2O3 is at a minimum set of subscripts, so no reducing is necessary. Not so in this next example.
Write the formula for barium oxide.
Write down the Ba2+ and O2¯ right next to each other, as in this image:
Move the positive charge (dropping the sign) to the subscript position of the anion:
Move the negative charge (dropping the sign) to the subscript position of the cation:
The result of all this moving is:
Since both subscripts have a common factor of two, we are not at a minimum set of subscripts. After reducing, the final answer is: