Permanganate half-reaction answer

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Here is the half-reaction in basic solution:

MnO₄¯ ---> MnO₂

Step One: Balance the half-reaction AS IF it were in acid solution.

3e¯ + 4H⁺ + MnO₄¯ ---> MnO₂ + 2H₂O

Step Two: Convert all H⁺ to H₂O.

3e¯ + 4H₂O + MnO₄¯ ---> MnO₂ + 2H₂O + 4OH¯

Step Three: Remove any duplicate molecules or ions.

3e¯ + 2H₂O + MnO₄¯ ---> MnO₂ + 4OH¯

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